8^2x-3=(1/6)^x-2

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Solution for 8^2x-3=(1/6)^x-2 equation: 



8^2x-3=(1/6)^x-2

We move all terms to the left:

8^2x-3-((1/6)^x-2)=0



Domain of the equation: 6)^x-2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

8^2x-((+1/6)^x-2)-3=0

We multiply all the terms by the denominator


8^2x*6)^x-2)-((-3*6)^x-2)+1=0

We add all the numbers together, and all the variables

8^2x*6)^x-2)-((-18)^x-2)+1=0

Wy multiply elements

48x^3-18)^x-2)+1=0

We do not support expression: x^3

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